What is the number of motor revolutions in the advertising engraving machine?

The number of revolutions of the motor = 120 times the power frequency divided by the number of motor poles.

In other words, the number of revolutions of the four-pole motor = 120 times 50 divided by 4 = 1500 rpm.

2-pole motor 3000 rpm

6 pole motor 1000 rpm

The impact of the increase in the number of motor revolutions in the advertising engraving machine?

1. Increasing the spindle speed will result in more heat of cutting: the heat of cutting has a very large influence on the service life of the tool. Why does each material have a reasonable cutting line speed? It is to limit the generation of cutting heat.

2, increase the spindle speed can reduce the amount of knife per revolution per tooth: the amount of knife per revolution per tooth = feed rate / (spindle speed * number of teeth), reduce the amount of knife per tooth per revolution can reduce the cutting force To make the processing smooth.

3. Increasing the spindle speed can increase the output power of the spindle motor: It can be seen from the power curve of our spindle motor that the higher the speed, the greater the output power, and the smoother the processing.

In general, it is beneficial to have a higher spindle speed, but at a reasonable speed range because it is the most important factor in tool life.

How to calculate the motor parameters of the advertising engraving machine?

1, first know the lead screw, the lead screw of the lead 5 is the spacing of each two wires is 5;

2, the stepper motor is 1.8 degrees 200 steps, walking a circle is 200 × 1.8 = 360 degrees

3, the drive is 8 subdivision is to divide 1.8 into 8 times

4, so each step of the motor through the drive is 1.8 degrees ÷ 8 = 0.225 degrees

5, so every turn is 200 × 8 = 1600 steps

6. The lead screw of lead 5 goes 5 mm per turn, and each step is 5÷1600=0.003125 mm, which is the motor parameter. If the parameter of lead 3 is 0.001875, and so on.

7. Dividing 1 by the motor parameter is the pulse equivalent. For example: 1÷0.003125=320, which is how many steps are required for each 1 mm walk, which is the pulse equivalent.